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Чисто последовательная структура в 2D-представлении (последовательное суммирование)

C++ реализация:

int seqSum(const std::vector<int>& _src)
{
   int resSum = 0;
   for (int srcId = 0; srcId < _src.size(); ++srcId)
   {
      resSum += _src[srcId];
   }
   return resSum;
}

Кодировка в XML:

<?xml version="1.0" encoding="UTF-8"?>
<algograph version="0.0.1">
   <algorithm num_ext_params="1" num_groups="2">
      <ext_param name="n"/>
      <group id="0" num_or_parts="1" num_oper="1">
         <or_part id="0" num_and_parts="1">
            <and_part id="0"><![CDATA[]]></and_part>
            <statement id="0" num_inputs="1">
               <input id="0" num_solutions="0"/>
            </statement>
         </or_part>
      </group>
      <loop>
         <loop>
            <group id="1" num_or_parts="1" num_oper="1">
               <or_part id="0" num_and_parts="4">
                  <and_part id="0"><![CDATA[-i1<=-1]]></and_part>
                  <and_part id="1"><![CDATA[i1<=n]]></and_part>
                  <and_part id="2"><![CDATA[-i2<=-1]]></and_part>
                  <and_part id="3"><![CDATA[i2<=n]]></and_part>
                  <statement id="0" num_inputs="3">
                     <input id="0" num_solutions="0"/>
                     <input id="1" num_solutions="3">
                        <solution num_altareas="1" group_id="1" or_part_id="0" statement_id="0" dimsolut="2">
                           <altarea num_conditions="5">
                              <condition><![CDATA[i2-n<=0]]></condition>
                              <condition><![CDATA[-n+2<=0]]></condition>
                              <condition><![CDATA[i1-n<=0]]></condition>
                              <condition><![CDATA[-i1+1<=0]]></condition>
                              <condition><![CDATA[-i2+2<=0]]></condition>
                           </altarea>
                           <dependency>
                              <coordinate><![CDATA[i1]]></coordinate>
                              <coordinate><![CDATA[i2-1]]></coordinate>
                           </dependency>
                        </solution>
                        <solution num_altareas="1" group_id="1" or_part_id="0" statement_id="0" dimsolut="2">
                           <altarea num_conditions="5">
                              <condition><![CDATA[-i2+1<=0]]></condition>
                              <condition><![CDATA[-n+2<=0]]></condition>
                              <condition><![CDATA[i1-n<=0]]></condition>
                              <condition><![CDATA[-i1+2<=0]]></condition>
                              <condition><![CDATA[i2-1<=0]]></condition>
                           </altarea>
                           <dependency>
                              <coordinate><![CDATA[i1-1]]></coordinate>
                              <coordinate><![CDATA[n]]></coordinate>
                           </dependency>
                        </solution>
                        <solution num_altareas="1" group_id="0" or_part_id="0" statement_id="0" dimsolut="0">
                           <altarea num_conditions="5">
                              <condition><![CDATA[-n+1<=0]]></condition>
                              <condition><![CDATA[-i2+1<=0]]></condition>
                              <condition><![CDATA[-i1+1<=0]]></condition>
                              <condition><![CDATA[i2-1<=0]]></condition>
                              <condition><![CDATA[i1-1<=0]]></condition>
                           </altarea>
                       </solution>
                     </input>
                     <input id="2" num_solutions="0"/>
                  </statement>
               </or_part>
            </group>
         </loop>
      </loop>
   </algorithm>
</algograph>

Новая разметка:

<algo>
   <params>
	<param name = "N" type = "int"></param>
   </params>
   <block dims = "2">
	<arg name = "i" val = "1..N"></arg>
	<arg name = "j" val = "1..N"></arg>

	<vertex condition = "(j == 1)" type = "0">
		<in src = “i  1, N”></in>
	</vertex>
	<vertex condition = "(j > 1)" type = "0">
		<in src = “i, j - 1”></in>
	</vertex>
   </block>
</algo>


Набор одномерных последовательных структур, независимых между собой - 2D вариант

C++ реализация:

void seqParSum(const std::vector<std::vector<int> >& _src, std::vector<int>& _res)
{
   if (_src.size() != _res.size())
      return;

   for (int srcGrpId = 0; srcGrpId < _src.size(); ++srcGrpId)
   {
      for (int srcElId = 0; srcElId < _src[srcGrpId].size(); ++srcElId )
      {
         _res[srcGrpId] += _src[srcGrpId][srcElId];
      }
   }
   return;
}

Кодировка в XML:

<?xml version="1.0" encoding="UTF-8"?>
<algograph version="0.0.1">
   <algorithm num_ext_params="1" num_groups="2">
      <ext_param name="n"/>
      <group id="0" num_or_parts="1" num_oper="1">
         <or_part id="0" num_and_parts="1">
            <and_part id="0"><![CDATA[]]></and_part>
            <statement id="0" num_inputs="1">
               <input id="0" num_solutions="0"/>
            </statement>
         </or_part>
      </group>
      <loop>
         <loop>
            <group id="1" num_or_parts="1" num_oper="1">
               <or_part id="0" num_and_parts="4">
                  <and_part id="0"><![CDATA[-i1<=-1]]></and_part>
                  <and_part id="1"><![CDATA[i1<=n]]></and_part>
                  <and_part id="2"><![CDATA[-i2<=-1]]></and_part>
                  <and_part id="3"><![CDATA[i2<=n]]></and_part>
                  <statement id="0" num_inputs="3">
                     <input id="0" num_solutions="0"/>
                     <input id="1" num_solutions="3">
                        <solution num_altareas="1" group_id="1" or_part_id="0" statement_id="0" dimsolut="2">
                           <altarea num_conditions="5">
                              <condition><![CDATA[i2-n<=0]]></condition>
                              <condition><![CDATA[-n+2<=0]]></condition>
                              <condition><![CDATA[i1-n<=0]]></condition>
                              <condition><![CDATA[-i1+1<=0]]></condition>
                              <condition><![CDATA[-i2+2<=0]]></condition>
                           </altarea>
                           <dependency>
                              <coordinate><![CDATA[i1]]></coordinate>
                              <coordinate><![CDATA[i2-1]]></coordinate>
                           </dependency>
                        </solution>
                        <solution num_altareas="1" group_id="1" or_part_id="0" statement_id="0" dimsolut="0">
                           <altarea num_conditions="5">
                              <condition><![CDATA[-i2+1<=0]]></condition>
                              <condition><![CDATA[-n+2<=0]]></condition>
                              <condition><![CDATA[i1-n<=0]]></condition>
                              <condition><![CDATA[-i1+2<=0]]></condition>
                              <condition><![CDATA[i2-1<=0]]></condition>
                           </altarea>
                        </solution>
                        <solution num_altareas="1" group_id="0" or_part_id="0" statement_id="0" dimsolut="0">
                           <altarea num_conditions="5">
                              <condition><![CDATA[-n+1<=0]]></condition>
                              <condition><![CDATA[-i2+1<=0]]></condition>
                              <condition><![CDATA[-i1+1<=0]]></condition>
                              <condition><![CDATA[i2-1<=0]]></condition>
                              <condition><![CDATA[i1-1<=0]]></condition>
                           </altarea>
                        </solution>
                     </input>
                     <input id="2" num_solutions="0"/>
                  </statement>
               </or_part>
            </group>
         </loop>
      </loop>
   </algorithm>
</algograph>

Новая разметка:

<algo>
   <params>
	<param name = "N" type = "int"></param>
   </params>
   <block dims = "2">
	<arg name = "i" val = "1..N"></arg>
	<arg name = "j" val = "1..N"></arg>

	<vertex condition = "" type = "0">
		<in src = “i, j - 1”></in>
	</vertex>
   </block>
</algo>


Двумерная структура со скошенным параллелизмом

C++ реализация:

int accumSum(int** _src, int _nCol, int _nRow)
{
   for (int rowId = 0; rowId < _nRow; ++rowId)
   {
      for (int colId = 0; colId < _nCol; ++colId)
      {
         _src[rowId][colId] += _src[rowId][colId == 0 ? colId : colId - 1];
         _src[rowId][colId] += _src[rowId == 0 ? rowId : rowId - 1][colId];
      }
   }
   return _src[_nRow - 1][_nCol - 1];
}

Кодировка в XML:

<?xml version="1.0" encoding="UTF-8"?>
<algograph version="0.0.1">
   <algorithm num_ext_params="1" num_groups="2">
      <ext_param name="n"/>
      <group id="0" num_or_parts="1" num_oper="1">
         <or_part id="0" num_and_parts="1">
            <and_part id="0"><![CDATA[]]></and_part>
            <statement id="0" num_inputs="1">
               <input id="0" num_solutions="0"/>
            </statement>
         </or_part>
      </group>
      <loop>
         <loop>
            <group id="1" num_or_parts="1" num_oper="1">
               <or_part id="0" num_and_parts="4">
                  <and_part id="0"><![CDATA[-i1<=-1]]></and_part>
                  <and_part id="1"><![CDATA[i1<=n]]></and_part>
                  <and_part id="2"><![CDATA[-i2<=-1]]></and_part>
                  <and_part id="3"><![CDATA[i2<=n]]></and_part>
                  <statement id="0" num_inputs="3">
                     <input id="0" num_solutions="0"/>
                     <input id="1" num_solutions="3">
                        <solution num_altareas="1" group_id="1" or_part_id="0" statement_id="0" dimsolut="2">
                           <altarea num_conditions="5">
                              <condition><![CDATA[i2-n<=0]]></condition>
                              <condition><![CDATA[-n+2<=0]]></condition>
                              <condition><![CDATA[i1-n<=0]]></condition>
                              <condition><![CDATA[-i1+1<=0]]></condition>
                              <condition><![CDATA[-i2+2<=0]]></condition>
                           </altarea>
                           <dependency>
                              <coordinate><![CDATA[i1]]></coordinate>
                              <coordinate><![CDATA[i2-1]]></coordinate>
                           </dependency>
                        </solution>
                        <solution num_altareas="1" group_id="1" or_part_id="0" statement_id="0" dimsolut="2">
                           <altarea num_conditions="5">
                              <condition><![CDATA[i2-n<=0]]></condition>
                              <condition><![CDATA[-n+2<=0]]></condition>
                              <condition><![CDATA[i1-n<=0]]></condition>
                              <condition><![CDATA[-i1+2<=0]]></condition>
                              <condition><![CDATA[-i2+1<=0]]></condition>
                           </altarea>
                           <dependency>
                              <coordinate><![CDATA[i1-1]]></coordinate>
                              <coordinate><![CDATA[i2]]></coordinate>
                           </dependency>
                        </solution>
                        <solution num_altareas="1" group_id="0" or_part_id="0" statement_id="0" dimsolut="0">
                           <altarea num_conditions="5">
                              <condition><![CDATA[-n+1<=0]]></condition>
                              <condition><![CDATA[-i2+1<=0]]></condition>
                              <condition><![CDATA[-i1+1<=0]]></condition>
                              <condition><![CDATA[i2-1<=0]]></condition>
                              <condition><![CDATA[i1-1<=0]]></condition>
                           </altarea>
                        </solution>
                     </input>
                     <input id="2" num_solutions="0"/>
                  </statement>
               </or_part>
            </group>
         </loop>
      </loop>
   </algorithm>
</algograph>

Новая разметка:

<algo>
   <params>
	<param name = "N" type = "int"></param>
   </params>
   <block dims = "2">
	<arg name = "i" val = "1..N"></arg>
	<arg name = "j" val = "1..N"></arg>

	<vertex condition = "" type = "0">
		<in src = “i, j - 1”></in>
		<in src = “i - 1, j”></in>
	</vertex>
   </block>
</algo>


Двумерная структура со скошенным параллелизмом и скошенной передачей данных

C++ реализация:

int accumSum(int** _src, int _nCol, int _nRow)
{
   for (int rowId = 0; rowId < _nRow; ++rowId)
   {
      for (int colId = 0; colId < _nCol; ++colId)
      {
         _src[rowId][colId] += _src[(rowId == 0 && colId < 2) ? rowId : rowId - 1][(rowId != 0 && colId > 1) ? colId : colId - 2];
         _src[rowId][colId] += _src[rowId == 0 ? rowId : rowId - 1][colId];
      }
   }
   return _src[_nRow - 1][_nCol - 1];
}

Кодировка в XML:

<?xml version="1.0" encoding="UTF-8"?>
<algograph version="0.0.1">
   <algorithm num_ext_params="1" num_groups="2">
      <ext_param name="n"/>
      <group id="0" num_or_parts="1" num_oper="1">
         <or_part id="0" num_and_parts="1">
            <and_part id="0"><![CDATA[]]></and_part>
            <statement id="0" num_inputs="1">
               <input id="0" num_solutions="0"/>
            </statement>
         </or_part>
      </group>
      <loop>
         <loop>
            <group id="1" num_or_parts="1" num_oper="1">
               <or_part id="0" num_and_parts="4">
                  <and_part id="0"><![CDATA[-i1<=-1]]></and_part>
                  <and_part id="1"><![CDATA[i1<=n]]></and_part>
                  <and_part id="2"><![CDATA[-i2<=-1]]></and_part>
                  <and_part id="3"><![CDATA[i2<=n]]></and_part>
                  <statement id="0" num_inputs="3">
                     <input id="0" num_solutions="0"/>
                     <input id="1" num_solutions="3">
                        <solution num_altareas="1" group_id="1" or_part_id="0" statement_id="0" dimsolut="2">
                           <altarea num_conditions="5">
                              <condition><![CDATA[i2-n<=0]]></condition>
                              <condition><![CDATA[-n+2<=0]]></condition>
                              <condition><![CDATA[i1-n<=0]]></condition>
                              <condition><![CDATA[-i1+1<=0]]></condition>
                              <condition><![CDATA[-i2+2<=0]]></condition>
                           </altarea>
                           <dependency>
                              <coordinate><![CDATA[i1]]></coordinate>
                              <coordinate><![CDATA[i2-1]]></coordinate>
                           </dependency>
                        </solution>
                        <solution num_altareas="1" group_id="1" or_part_id="0" statement_id="0" dimsolut="2">
                           <altarea num_conditions="5">
                              <condition><![CDATA[i2-n<=0]]></condition>
                              <condition><![CDATA[-n+2<=0]]></condition>
                              <condition><![CDATA[i1-n<=0]]></condition>
                              <condition><![CDATA[-i1+3<=0]]></condition>
                              <condition><![CDATA[-i2+2<=0]]></condition>
                           </altarea>
                           <dependency>
                              <coordinate><![CDATA[i1-2]]></coordinate>
                              <coordinate><![CDATA[i2-1]]></coordinate>
                           </dependency>
                        </solution>
                        <solution num_altareas="1" group_id="0" or_part_id="0" statement_id="0" dimsolut="0">
                           <altarea num_conditions="5">
                              <condition><![CDATA[-n+1<=0]]></condition>
                              <condition><![CDATA[-i2+1<=0]]></condition>
                              <condition><![CDATA[-i1+1<=0]]></condition>
                              <condition><![CDATA[i2-1<=0]]></condition>
                              <condition><![CDATA[i1-n<=0]]></condition>
                           </altarea>
                        </solution>
                     </input>
                     <input id="2" num_solutions="0"/>
                  </statement>
               </or_part>
            </group>
         </loop>
      </loop>
   </algorithm>
</algograph>

Новая разметка:

<algo>
   <params>
	<param name = "N" type = "int"></param>
   </params>
   <block dims = "2">
	<arg name = "i" val = "1..N"></arg>
	<arg name = "j" val = "1..N"></arg>

	<vertex condition = "" type = "0">
		<in src = “i, j - 1”></in>
		<in src = “i - 2, j - 1”></in>
	</vertex>
   </block>
</algo>


Двумерная структура с квадратным параллелизмом и массовыми рассылками по каждому измерению

C++ реализация:

int accumSum(int** _src, int _nCol, int _nRow)
{
   for (int rowId = 0; rowId < _nRow; ++rowId)
   {
      for (int colId = 0; colId < _nCol; ++colId)
      {
         _src[rowId][colId] += _src[rowId][colId == 0 ? colId : colId - 1];
         _src[rowId][colId] += _src[rowId == 0 ? rowId : rowId - 1][colId];
         _src[rowId][colId] += _src[rowId][0];
         _src[rowId][colId] += _src[0][colId];
      }
   }
   return _src[_nRow - 1][_nCol - 1];
}

Кодировка в XML:

<?xml version="1.0" encoding="UTF-8"?>
<algograph version="0.0.1">
   <algorithm num_ext_params="1" num_groups="2">
      <ext_param name="n"/>
      <group id="0" num_or_parts="1" num_oper="1">
         <or_part id="0" num_and_parts="1">
            <and_part id="0"><![CDATA[]]></and_part>
            <statement id="0" num_inputs="1">
               <input id="0" num_solutions="0"/>
            </statement>
         </or_part>
      </group>
      <loop>
         <loop>
            <group id="1" num_or_parts="1" num_oper="1">
               <or_part id="0" num_and_parts="4">
                  <and_part id="0"><![CDATA[-i1<=-1]]></and_part>
                  <and_part id="1"><![CDATA[i1<=n]]></and_part>
                  <and_part id="2"><![CDATA[-i2<=-1]]></and_part>
                  <and_part id="3"><![CDATA[i2<=n]]></and_part>
                  <statement id="0" num_inputs="3">
                     <input id="0" num_solutions="0"/>
                     <input id="1" num_solutions="5">
                        <solution num_altareas="1" group_id="1" or_part_id="0" statement_id="0" dimsolut="2">
                           <altarea num_conditions="5">
                              <condition><![CDATA[i2-n<=0]]></condition>
                              <condition><![CDATA[-n+2<=0]]></condition>
                              <condition><![CDATA[i1-n<=0]]></condition>
                              <condition><![CDATA[-i1+1<=0]]></condition>
                              <condition><![CDATA[-i2+2<=0]]></condition>
                           </altarea>
                           <dependency>
                              <coordinate><![CDATA[i1]]></coordinate>
                              <coordinate><![CDATA[i2-1]]></coordinate>
                           </dependency>
                        </solution>
                        <solution num_altareas="1" group_id="1" or_part_id="0" statement_id="0" dimsolut="2">
                           <altarea num_conditions="5">
                              <condition><![CDATA[i2-n<=0]]></condition>
                              <condition><![CDATA[-n+2<=0]]></condition>
                              <condition><![CDATA[i1-n<=0]]></condition>
                              <condition><![CDATA[-i2+1<=0]]></condition>
                              <condition><![CDATA[-i1+2<=0]]></condition>
                           </altarea>
                           <dependency>
                              <coordinate><![CDATA[i1-1]]></coordinate>
                              <coordinate><![CDATA[i2]]></coordinate>
                           </dependency>
                        </solution>
                        <solution num_altareas="1" group_id="1" or_part_id="0" statement_id="0" dimsolut="2">
                           <altarea num_conditions="5">
                              <condition><![CDATA[i2-n<=0]]></condition>
                              <condition><![CDATA[-n+2<=0]]></condition>
                              <condition><![CDATA[i1-n<=0]]></condition>
                              <condition><![CDATA[-i1+1<=0]]></condition>
                              <condition><![CDATA[-i2+3<=0]]></condition>
                           </altarea>
                           <dependency>
                              <coordinate><![CDATA[i1]]></coordinate>
                              <coordinate><![CDATA[1]]></coordinate>
                           </dependency>
                        </solution>
                        <solution num_altareas="1" group_id="1" or_part_id="0" statement_id="0" dimsolut="2">
                           <altarea num_conditions="5">
                              <condition><![CDATA[i2-n<=0]]></condition>
                              <condition><![CDATA[-n+2<=0]]></condition>
                              <condition><![CDATA[i1-n<=0]]></condition>
                              <condition><![CDATA[-i2+1<=0]]></condition>
                              <condition><![CDATA[-i1+3<=0]]></condition>
                           </altarea>
                           <dependency>
                              <coordinate><![CDATA[1]]></coordinate>
                              <coordinate><![CDATA[i2]]></coordinate>
                           </dependency>
                        </solution>
                        <solution num_altareas="1" group_id="0" or_part_id="0" statement_id="0" dimsolut="0">
                           <altarea num_conditions="5">
                              <condition><![CDATA[-n+1<=0]]></condition>
                              <condition><![CDATA[-i2+1<=0]]></condition>
                              <condition><![CDATA[-i1+1<=0]]></condition>
                              <condition><![CDATA[i2-1<=0]]></condition>
                              <condition><![CDATA[i1-n<=0]]></condition>
                           </altarea>
                        </solution>
                     </input>
                     <input id="2" num_solutions="0"/>
                  </statement>
               </or_part>
            </group>
         </loop>
      </loop>
   </algorithm>
</algograph>

Новая разметка:

<algo>
   <params>
	<param name = "N" type = "int"></param>
   </params>
   <block dims = "2">
	<arg name = "i" val = "1..N"></arg>
	<arg name = "j" val = "1..N"></arg>
	<vertex condition = "" type = "0">
		<in src = “i, j - 1”></in>
		<in src = “i - 1, j”></in>
		<in src = “1, j”></in>
		<in src = “i, 1”></in>
	</vertex>
   </block>
</algo>


Набор независимых последовательно-параллельных 2D-структур с массовой рассылкой данных в каждой

C++ реализация:

void accumSum(int*** _src, int _nCol, int _nRow, int _nLayer)
{
   for (int layerId = 0; layerId < _nLayer; ++layerId)
   {
      for (int rowId = 0; rowId < _nRow; ++rowId)
      {
         for (int colId = 0; colId < _nCol; ++colId)
         {
            _src[layerId][rowId][colId] += _src[layerId][rowId == 0 ? rowId : rowId - 1][colId == 0 ? colId : 0];
            _src[layerId][rowId][colId] += _src[layerId][rowId == 0 ? rowId : rowId - 1][colId];
         }
      }   
   }
}

Кодировка в XML:

<?xml version="1.0" encoding="UTF-8"?>
<algograph version="0.0.1">
   <algorithm num_ext_params="2" num_groups="2">
      <ext_param name="n"/>
      <ext_param name="m"/>
         <group id="0" num_or_parts="1" num_oper="1">
         <or_part id="0" num_and_parts="1">
            <and_part id="0"><![CDATA[]]></and_part>
            <statement id="0" num_inputs="1">
               <input id="0" num_solutions="0"/>
            </statement>
         </or_part>
      </group>
      <loop>
         <loop>
            <loop>
               <group id="1" num_or_parts="1" num_oper="1">
                  <or_part id="0" num_and_parts="6">
                     <and_part id="0"><![CDATA[-i1<=-1]]></and_part>
                     <and_part id="1"><![CDATA[i1<=n]]></and_part>
                     <and_part id="2"><![CDATA[-i2<=-1]]></and_part>
                     <and_part id="3"><![CDATA[i2<=m]]></and_part>
                     <and_part id="4"><![CDATA[i3>=0]]></and_part>
                     <and_part id="5"><![CDATA[i3<=n-1]]></and_part>
                        <input id="0" num_solutions="0"/>
                        <input id="1" num_solutions="3">
                           <solution num_altareas="1" group_id="1" or_part_id="0" statement_id="0" dimsolut="3">
                              <altarea num_conditions="7">
                                 <condition><![CDATA[-m+2<=0]]></condition>
                                 <condition><![CDATA[i1-n<=0]]></condition>
                                 <condition><![CDATA[i3-n+1<=0]]></condition>
                                 <condition><![CDATA[-i2+2<=0]]></condition>
                                 <condition><![CDATA[i2<=m]]></condition>
                                 <condition><![CDATA[-i1+1<=0]]></condition>
                                 <condition><![CDATA[-i3<=0]]></condition>
                              </altarea>
                              <dependency>
                                 <coordinate><![CDATA[i1]]></coordinate>
                                 <coordinate><![CDATA[i2-1]]></coordinate>
                                 <coordinate><![CDATA[i3]]></coordinate>
                              </dependency>
                           </solution>
                           <solution num_altareas="1" group_id="1" or_part_id="0" statement_id="0" dimsolut="3">
                              <altarea num_conditions="7">
                                 <condition><![CDATA[-m+2<=0]]></condition>
                                 <condition><![CDATA[i1-n<=0]]></condition>
                                 <condition><![CDATA[i3-n+1<=0]]></condition>
                                 <condition><![CDATA[-i2+2<=0]]></condition>
                                 <condition><![CDATA[i2<=m]]></condition>
                                 <condition><![CDATA[-i1+1<=0]]></condition>
                                 <condition><![CDATA[-i3<=0]]></condition>
                              </altarea>
                              <dependency>
                                 <coordinate><![CDATA[1]]></coordinate>
                                 <coordinate><![CDATA[i2-1]]></coordinate>
                                 <coordinate><![CDATA[i3]]></coordinate>
                              </dependency>
                           </solution>									
                           <solution num_altareas="1" group_id="0" or_part_id="0" statement_id="0" dimsolut="0">
                              <altarea num_conditions="6">
                                 <condition><![CDATA[i2-1<=0]]></condition>
                                 <condition><![CDATA[i2-1>=0]]></condition>
                                 <condition><![CDATA[-i1+1<=0]]></condition>
                                 <condition><![CDATA[-i3<=0]]></condition>
                                 <condition><![CDATA[i1-n<=0]]></condition>
                                 <condition><![CDATA[i3-n+1<=0]]></condition>
                              </altarea>
                           </solution>
                        </input>
                        <input id="2" num_solutions="0"/>
                     </statement>
                  </or_part>
               </group>
            </loop>
         </loop>
      </loop>
   </algorithm>
</algograph>

Новая разметка:

<algo>
   <params>
	<param name = "N" type = "int"></param>
   </params>
   <block dims = "3">
	<arg name = "i" val = "1..N"></arg>
	<arg name = "j" val = "1..N"></arg>
	<arg name = "k" val = "1..N"></arg>
	<vertex condition = "" type = "0">
		<in src = “i, j  1, k”></in>
		<in src = “1, j - 1, k”></in>
	</vertex>
   </block>
</algo>


Набор одномерных последовательных структур, независимых между собой - 3D вариант

C++ реализация:

void accumSum(int*** _src, int _nCol, int _nRow, int _nLayer)
{
   for (int layerId = 0; layerId < _nLayer; ++layerId)
   {
      for (int rowId = 0; rowId < _nRow; ++rowId)
      {
         for (int colId = 0; colId < _nCol; ++colId)
         {
            _src[layerId][rowId][colId] += _src[layerId][rowId == 0 ? rowId : rowId - 1][colId];
         }
      }   
   }
}

Кодировка в XML:

<?xml version="1.0" encoding="UTF-8"?>
<algograph version="0.0.1">
   <algorithm num_ext_params="2" num_groups="2">
      <ext_param name="n"/>
      <ext_param name="m"/>
      <group id="0" num_or_parts="1" num_oper="1">
         <or_part id="0" num_and_parts="1">
            <and_part id="0"><![CDATA[]]></and_part>
            <statement id="0" num_inputs="1">
               <input id="0" num_solutions="0"/>
            </statement>
         </or_part>
      </group>
      <loop>
         <loop>
            <loop>
               <group id="1" num_or_parts="1" num_oper="1">
                  <or_part id="0" num_and_parts="6">
                     <and_part id="0"><![CDATA[-i1<=-1]]></and_part>
                     <and_part id="1"><![CDATA[i1<=n]]></and_part>
                     <and_part id="2"><![CDATA[-i2<=-1]]></and_part>
                     <and_part id="3"><![CDATA[i2<=m]]></and_part>
                     <and_part id="4"><![CDATA[i3>=0]]></and_part>
                     <and_part id="5"><![CDATA[i3<=n-1]]></and_part>
                     <statement id="0" num_inputs="3">
                        <input id="0" num_solutions="0"/>
                        <input id="1" num_solutions="2">
                           <solution num_altareas="1" group_id="1" or_part_id="0" statement_id="0" dimsolut="3">
                              <altarea num_conditions="7">
                                 <condition><![CDATA[-m+2<=0]]></condition>
                                 <condition><![CDATA[i1-n<=0]]></condition>
                                 <condition><![CDATA[i3-n+1<=0]]></condition>
                                 <condition><![CDATA[-i2+1<=0]]></condition>
                                 <condition><![CDATA[i2+1<=m]]></condition>
                                 <condition><![CDATA[-i1+1<=0]]></condition>
                                 <condition><![CDATA[-i3<=0]]></condition>
                              </altarea>
                              <dependency>
                                 <coordinate><![CDATA[i1]]></coordinate>
                                 <coordinate><![CDATA[i2+1]]></coordinate>
                                 <coordinate><![CDATA[i3]]></coordinate>
                              </dependency>
                           </solution>
                           <solution num_altareas="1" group_id="0" or_part_id="0" statement_id="0" dimsolut="0">
                              <altarea num_conditions="6">
                                 <condition><![CDATA[i2-m<=0]]></condition>
                                 <condition><![CDATA[i2-m>=0]]></condition>
                                 <condition><![CDATA[-i1+1<=0]]></condition>
                                 <condition><![CDATA[-i3<=0]]></condition>
                                 <condition><![CDATA[i1-n<=0]]></condition>
                                 <condition><![CDATA[i3-n+1<=0]]></condition>
                              </altarea>
                           </solution>
                        </input>
                        <input id="2" num_solutions="0"/>
                     </statement>
                  </or_part>
               </group>
            </loop>
         </loop>
      </loop>
   </algorithm>
</algograph>

Новая разметка:

<algo>
   <params>
	<param name = "N" type = "int"></param>
   </params>
   <block dims = "3">
	<arg name = "i" val = "1..N"></arg>
	<arg name = "j" val = "1..N"></arg>
	<arg name = "k" val = "1..N"></arg>

	<vertex condition = "" type = "0">
		<in src = “i, j  1, k”></in>
	</vertex>
   </block>
</algo>


Пример массовой рассылки данных в 2D-структуре

Новая разметка:

<algo>
   <params>
	<param name = "N" type = "int"></param>
   </params>
   <block dims = "2">
	<arg name = "i" val = "1..N"></arg>
	<arg name = "j" val = "1..2"></arg>

	<vertex condition = "(j == 1) && (i == 1)" type = "0">
	</vertex>
	<vertex condition = "(j > 1)" type = "0">
		<in src = “1, 1”></in>
	</vertex>
   </block>
</algo>


Последовательный набор 3D-структур, содержащих скошенный параллелизм

Новая разметка:

<algo>
   <params>
	<param name = "N" type = "int"></param>
   </params>
   <block id = "0" dims = "3">
	<arg name = "i" val = "1..N"></arg>
	<arg name = "j" val = "1..N"></arg>
        <arg name = "k" val = "1..N"></arg>
	<vertex condition = "" type = "0">
		<in src = "i - 1, j, k"></in>
		<in src = "i, j – 1, k"></in>
		<in src = "i, j, k - 1"></in>
	</vertex>
   </block>
   <block id = "1" dims = "3">
	<arg name = "i" val = "1..N"></arg>
	<arg name = "j" val = "1..2"></arg>
        <arg name = "k" val = "1..N"></arg>
	<vertex condition = "" type = "0">
		<in bsrc = "0" src = "i, j, k"></in>
		<in src = "i - 1, j, k"></in>
		<in src = "i, j – 1, k"></in>
		<in src = "i, j, k - 1"></in>
	</vertex>
   </block>
</algo>


Пример массовой рассылки данных в 3D-структуре

Новая разметка:

<algo>
   <params>
	<param name = "N" type = "int"></param>
   </params>
   <block dims = "3">
	<arg name = "i" val = "1..N"></arg>
	<arg name = "j" val = "1..N"></arg>
        <arg name = "k" val = "1..2"></arg>
	<vertex condition = "(i == 1) && (j == 1) && (k == 1)" type = "0">
	</vertex>
	<vertex condition = "(i > 1) && (j > 1) && (k > 1)" type = "0">
		<in src = “1, 1, 1”></in>
	</vertex>
   </block>
</algo>


Пример 3D-структуры с различными видами скошенного параллелизма

Новая разметка:

<algo>
   <params>
	<param name = "N" type = "int"></param>
   </params>
   <block dims = "3">
	<arg name = "i" val = "1..N"></arg>
	<arg name = "j" val = "1..N"></arg>
        <arg name = "k" val = "1..2"></arg>
	<vertex condition = "k == 1" type = "0">
		<in src = “i, j  1”></in>
		<in src = “i - 1, j”></in>
	</vertex>
	<vertex condition = "k > 1" type = "0">
		<in src = “i, j, 1”></in>
		<in src = “i, j  1”></in>
		<in src = “i - 1, j - 1”></in>
	</vertex>
   </block>
</algo>


Последовательно-параллельное перемножение матриц

Новая разметка:

<algo>
   <params>
	<param name = "N" type = "int"></param>
	<param name = "P" type = "int"></param>
	<param name = "Q" type = "int"></param>
   </params>
   <block dims = "3">
	<arg name = "i" val = "1..N"></arg>
	<arg name = "j" val = "1..P"></arg>
        <arg name = "k" val = "1..Q"></arg>
	<vertex condition = "(i > 1) && (j > 1)" type = "0">
		<in src = “i, j  1”></in>
		<in src = “i - 1, j”></in>
		<in src = “i, j, k -1”></in>
	</vertex>
	<vertex condition = "(i > 1) || (j > 1)" type = "0">
		<in src = “i, j  1”></in>
		<in src = “i - 1, j”></in>
	</vertex>
   </block>
</algo>